A balloon rises up with constant net acceleration of 10 m/s 2 . After 2 s a particle drops from the balloon. After further 2s match the following : (Take g = 10 m/s 2 )
Column-I | Column-II |
(i) Height of particle Ground | [A] Zero |
(ii) Speed of particle | [B] 10 SI units |
(iii) Displacement of particle | [C] 40 SI units |
(iv) Acceleration of Particle | [D] 20 SI units |
Text Solution
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Ans.
(i) [C]
(ii) [A]
(iii) [D]
(iv) [B]
Sol. After 2s velocity of balloon and hence the velocity of the particle will be 20 m/s (= at) and its height from the ground will be 20 m 
. Now g, will stare acting on the particle.
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